SOLUTION: If Kyle drove the first 40 miles and I droved the last leg of the drive. Taking the same route home Kyle drove the first leg and I drove the last 50 miles. Who drove the most a

Question 535914: If Kyle drove the first 40 miles and I droved the last leg of the drive. Taking the same route home Kyle drove the first leg and I drove the last 50 miles.
Who drove the most and by how much?
I have tried putting this into a trigonometry distance formula as well as an algerbraic formula (40x=50x) then dividing them both by 50 which will become: x=40x/50, I configured it to x=.8x. I am lost on where to go from there if I am even on the correct track. Thank you for your time and help.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If Kyle drove the first 40 miles and I droved the last leg of the drive.
Taking the same route home Kyle drove the first leg and I drove the last 50 miles.
Who drove the most and by how much?
:
Let h = dist of the last leg of the outbound trip (which he drove)
then
(h+40) = total one-way distance
:
"Taking the same route home Kyle drove the first leg and I drove the last 50 miles."
Find the dist Kyle drove (k)
K = (h+40) - 50
k = h - 10
Therefore h drove 10 more miles than k (Kyle)
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