SOLUTION: Josh is skating a pond. He moves at 10 mph going from one end to the other, but on his way back he comes 5 mph. It took him one hour. How long is the pond?
i tried 10(x-1) + 5(x
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i tried 10(x-1) + 5(x
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Question 534095: Josh is skating a pond. He moves at 10 mph going from one end to the other, but on his way back he comes 5 mph. It took him one hour. How long is the pond?
i tried 10(x-1) + 5(x) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Josh is skating a pond. He moves at 10 mph going from one end to the other, but on his way back he comes 5 mph. It took him one hour. How long is the pond?
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The avg speed for the round trip is
2*10*5/(10+5) = 100/15 mi/hr
d = r*t = (100/15) mi/hr * 1hr = 20/3 miles RT
--> 10/3 miles one-way
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Avg speed for a round trip is alway 2*r1*r2/(r1 + r2)
You can work that out, or take my word for it.
