SOLUTION: My math question is: Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jorda

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Question 530936: My math question is:
Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?
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Jordan DATA:
rate = 7 mph ; distance = x miles ; time = x/7 hrs = (60/7)x minutes
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Steve DATA:
rate = 6 mph ; distance = x-5 miles ; time = (x-5)/6 hrs = 10*(x-5) minutes
=================
Equation:
(60/7)x = 10(x-5)
60x = 70x - 350
10x = 350
x = 35 miles
----
Time Jordan needed to catch Steve:
(60/7)x = 60/7 * 35 = 300 minutes = 5 hours
==============================
Quicker method:
At 7 mph Jordan gains 1 mile in 1 hour
So after 5 hours Jordan has caught up with Steve.
==============================
Cheers,
Stan H.
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