SOLUTION: A boat travels 15 miles upstream and returns. If the boat travels 14 mph in still water, find the speed of the currrent if the total trip takes 2 hours and 20 minutes.
I really
Algebra.Com
Question 530762: A boat travels 15 miles upstream and returns. If the boat travels 14 mph in still water, find the speed of the currrent if the total trip takes 2 hours and 20 minutes.
I really only want to understand how to set the problem up, I have no problem with the algebra part :). Thank you so much to whoever helps me.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A boat travels 15 miles upstream and returns.
If the boat travels 14 mph in still water, find the speed of the current if the total trip takes 2 hours and 20 minutes.
:
Let c = the speed of the current
then
(14+c) = effective speed downstream
and
(14-c) = effective speed upstream
:
Change 2 hrs 20 min to hrs
:
Write a time equation: time = dist/speed
:
Upstream time + downstream time = 2 hrs 20 min
= =
RELATED QUESTIONS
A boat travels upstream for 35 miles and then returns to its starting point. If the round (answered by josgarithmetic)
#1:
The speed of a stream is 6mph
If a boat travels 54 miles downstream in the same... (answered by ewatrrr)
a paddle boat travels 9 miles upstream (against the current) in the same time it travels (answered by jorel555)
A boat travels 100 miles downstream in the same length of time it travels 50 miles... (answered by mananth)
the speed of a boat in still water is 30 mph. It takes the same time for the boat to... (answered by josgarithmetic,greenestamps)
blake travels in a boat 200 miles downstream in the same time that it takes to go 120... (answered by checkley77)
The speed of a boat in still water is 24 mph. If the boat travels 54 miles upstream in... (answered by solver91311)
the speed of the lazy river current is 5 mph. If a boat travels 20 miles downstream in... (answered by Fombitz)
The speed of a boat in still water is 10 mph. If the boat travels 108 miles upstream in... (answered by stanbon)