SOLUTION: I need help!
A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?
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Question 529505: I need help!
A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?
thank you
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour.
What is that person's average rate for the trip?
:
Let a = the average speed of the 30 mi trip
:
Write a time equation, time = dist/speed
+ =
invert the dividing fraction and multiply
3(15) + 7(15) =
45 + 105 =
150 =
Multiply both sides by a
150a = 30
divide both sides by 150
a =
a = mph hr is the average speed
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
I need help!
A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?
Average rate = total distance, divided by total time
We then have:
, or , or mph
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