SOLUTION: Car A is traveling at 65 MPH and car B is traveling at 120 MPH. Car B passes car A. It takes car A 5 minutes and 4 seconds to catch up to car B after car B passed car A. At what sp

Question 528302: Car A is traveling at 65 MPH and car B is traveling at 120 MPH. Car B passes car A. It takes car A 5 minutes and 4 seconds to catch up to car B after car B passed car A. At what speed (MPH) does car A has to go to catch up to car B.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Car A is traveling at 65 MPH and car B is traveling at 120 MPH. Car B passes car A. It takes car A 5 minutes and 4 seconds to catch up to car B after car B passed car A. At what speed (MPH) does car A has to go to catch up to car B.
**
let x=speed over 120 (MPH) car A has to go to catch up to car B.
120+x=total speed (MPH) car A has to go to catch up to car B.
5 minutes and 4 seconds=5*60+4=304 seconds=(304/3600) hr
Distance car A traveled before car B catches up=(304/3600)*120≈10.13 mi
x=distance/travel time=10.13/(304/3600)=120 mph
ans:
total speed (MPH) car A has to go to catch up to car B=120+x=240 mph
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