SOLUTION: This question has to do with train speeds. Question: Train A leaves a station traveling at 20 mph. Eight hours later, Train B leaves the same station traveling in the same dir

Question 527727: This question has to do with train speeds.
Question: Train A leaves a station traveling at 20 mph. Eight hours later, Train B leaves the same station traveling in the same direction at 30 mph. How long does it take for Train B to catch up to Train A?
I have tried the Distance = Rate x Time equation, but not sure how to set up the problem to solve it. Rate: Train A = 20 mph; Train B = 30 mph. That's as far as I get. Please help.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
B catches up when it has traveled the same (equal) distance as A

(30)(t) = (20)(t + 8)

as a check ___ A travels 160 mi (8 * 20) before B leaves ___ B closes the gap at 10 mph (30 - 20) ___ how long to catch up
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