SOLUTION: At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 miles per hour. At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant s

Question 524114: At 1:00 p.m. a car leaves St. Louis for Chicago,
traveling at a constant speed of 65 miles per hour. At
2:00 p.m. a truck leaves Chicago for St. Louis,
traveling at a constant speed of 55 miles per hour. If it
is a 305-mile drive between St. Louis and Chicago, at
what time will the car and truck pass each other?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 miles per hour.
At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 miles per hour.
If it is a 305-mile drive between St. Louis and Chicago, at what time will the car and truck pass each other?
:
Let t = travel time of the car
then
(t-1) = travel time of the truck
:
Write a distance equation, dist = speed * time
:
When they meet, the sum of their distance traveled will be 305 mi
:
Car dist + Truck dist = 305 mi
65t + 55(t-1) = 305
65t + 55t - 55 = 305
65t + 55t = 305 + 55
120t = 360
t = 360/120
t = 3 hrs
Find the time of the meeting: 1:00 + 3:00 = 4 PM
:
:
Confirm this, find the distance each traveled
65(3) = 195 mi
55(2) = 110 mi
---------------
tot dist:305 mi

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