SOLUTION: The moving sidewalk at Chicago's O'Hare International Airport moves at a speed of 2.0 feet per second. Walking on the moving sidewalk, Nancy Killian walks 120 feet in the same time
Algebra.Com
Question 523342: The moving sidewalk at Chicago's O'Hare International Airport moves at a speed of 2.0 feet per second. Walking on the moving sidewalk, Nancy Killian walks 120 feet in the same time that it takes her to walk 52 feet without the moving sidewalk. How fast does Nancy walk?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Problem: The moving sidewalk at Chicago's O'Hare International Airport moves at a speed of 2.0 feet per second. Walking on the moving sidewalk, Nancy Killian walks 120 feet in the same time that it takes her to walk 52 feet without the moving sidewalk. How fast does Nancy walk?
.
Solution: Distance problems always use the fundamental distance equation:
.
d = r*t, where d=distance, r=rate, and t=time.
.
In this case we have two distances and one rate.
.
d = 120
r = w+2, where 'w' is Nancy's walking rate and 2 ft/sec is the speed of the moving sidewalk.
.
d1 = 52
r1 = w, where 'w' is Nancy's walking rate without an assist from a moving sidewalk.
.
At this point, we have too many unknowns to solve the equation.
But we have one addition bit of information that is very helpful: it takes the same time.
So, t = t1 or rather t=t.
That indicates we need to get both distance equations into t=something form to solve the problem.
.
With Moving Sidewalk
.
d = r*t
d = 120
r = w+2
t = 120/(w+2)
.
Without Moving Sidewalk
.
d1 = 52
r1 = w
t1 = 52/w
.
Transitive Property of Equality
.
We know t=t1, so that means:
.
120/(w+2) = 52/w
.
Cross-multiply.
.
120w = 52(w+2)
.
120w = 52w + 104
.
Subtract 52w from both sides.
.
120w -52w = (52w-52w) + 104 = 104
.
68w = 104
.
Divide both sides by 68.
.
w = 104/68 = 26/17
.
This solution indicates Nancy's walking speed is 26/17 ft/sec or approximately 1.529411764705882 ft/sec.
.
But always check your proposed solution to ensure it is the answer.
.
If w=1.529411764705882, how long does it take her to walk 52 ft?
52/1.529411764705882 = 34.00000000000001 sec.
.
If w+2 = 3.529411764705882, how long does it take her to walk 120 ft?
120/3.529411764705882 = 34.00000000000001 sec.
.
Correct.
.
Answer: Nancy's walking speed is 26/17 ft/sec or approximately 1.529411764705882 ft/sec.
RELATED QUESTIONS
At O Haire Airport in Chicago, Cheryl and Will are walking to their gate (at the same... (answered by stanbon)
a moving sidewalk at an airport glides at a rate of 1.2 feet per second. Walking on the... (answered by mananth)
saide and jose are in chicago o hare airport walking between terminals. sadie walks on... (answered by ankor@dixie-net.com)
A moving sidewalk at an airport is glides at a rate of 1.8 feet per second. Walking on... (answered by josmiceli,stanbon)
In order to access the outer part of Terminal 1 at O'Hare International Airport, you must (answered by Theo)
1. Radiation machines, used to treat tumors, produce an inensity of radiation that valies (answered by edjones)
sage has a walking speed of 300 feet per minute on the way to her at the airport saga has (answered by josgarithmetic)
walking on a moving sidewalk at an airport took only 7 minutes while walking at 5ft/sec... (answered by ankor@dixie-net.com)
The moving sidewalk at Chicago's O'Hare airport moves 1.8 ft/sec. Walking on the moving... (answered by stanbon,ankor@dixie-net.com)