SOLUTION: Two trains are 5000 feet apart, heading toward each other, but on separate parallel straight tracks, Train A is traveling at 45 miles per hour and Train B is traveling at 24 miles

Question 521688: Two trains are 5000 feet apart, heading toward each other, but on separate parallel straight tracks, Train A is traveling at 45 miles per hour and Train B is traveling at 24 miles per hour.
Change 45 miles per hour and 24 miles per hour into feet per second.

About how far will each train travel before they meet? Round your answers to the nearest hundredth.

In how many seconds will the trains meet?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two trains are 5000 feet apart, heading toward each other, but on separate parallel straight tracks,
Train A is traveling at 45 miles per hour and Train B is traveling at 24 miles per hour.
Change 45 miles per hour and 24 miles per hour into feet per second.
45 mph: = 66.0 ft/s
24 mph: = 35.2 ft/s
:
Let t = time (in sec) for them to meet, write a distance eq: dist = speed*time
66t + 35.2t = 5000
101.2t = 5000
t =
t = 49.41 seconds
:
About how far will each train travel before they meet? Round your answers to the nearest hundredth.
45 mph train: 49.41 * 66 = 3261.06 ft
24 mph train: 49.41* 35.2= 1739.23 ft
--------------------------------------
confirm this by adding: 5000.29 ~ 5000
:
In how many seconds will the trains meet? Like we said: 49.41 sec
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