SOLUTION: A cyclist leaves Toronto at 10am riding West. At noon, a car starts along the same road, driving 3 times as fast as the bike. When will the car catch up with the bike?
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Question 521501: A cyclist leaves Toronto at 10am riding West. At noon, a car starts along the same road, driving 3 times as fast as the bike. When will the car catch up with the bike?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
r*t=d
We don't know time and we don't know distance.
We know the car is 3 times as fast the bike.
We also know the distances are the same for the bike and the car.
We also know
r*(t+2)=d
3r*t=d
r*(t+2)=3*r*t
rt+2r=3rt
2r=2rt
1=t
They will meet in one hour.
Also
r*(t+2)=3*r*t
divide by r
t+2=3t
2=2t
1=t
They will meet in one hour
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