SOLUTION: Lee can walk 8 miles in the same time it takes Sabrina to walk 6 miles. If Lee walks 1 mile per hour faster than Sabrina, then how fast does each of them walk?

Question 518890: Lee can walk 8 miles in the same time it takes Sabrina to walk 6 miles. If Lee walks 1 mile per hour faster than Sabrina, then how fast does each of them walk?

Answer by Sohail Ahmed Khan(1) (Show Source): You can put this solution on YOUR website!
This would be my first solution here, so I may not be using the available tools fully.Any how:
LEE: covers 8 miles in T hours, this implies that his speed is: (8/T)miles/hour.
Sabrina: Covers 6 miles in T hours, this implies that her speed is: (6/T) miles/hour.
Now It is already told to us that the LEE speed is greater than Sabrina's speed by 1 miles/hour.
SO from above we get:
LEE Speed = Sabrina Speed + 1
8/T = 6/T +1
Solving for T gives T=2.
Hence LEE's speed is 4 miles/hour and Sabrina speed is 3 miles/hour.

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