SOLUTION: if one car goes thirty miles per hour, and another goes 60 miles per hour but leaves two hours later, when will the meet up

Question 517975: if one car goes thirty miles per hour, and another goes 60 miles per hour but leaves two hours later, when will the meet up
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if one car goes thirty miles per hour, and another goes 60 miles per hour but leaves two hours later, when will the meet up
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slower car DATA:
rate = 30 mph ; time = x hrs ; distance = rt = 30x miles
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faster car DATA:
rate = 60 mph ; time = x-2 hrs; distance = rt = 60(x-2) miles
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Equation:
distance = distance
30x = 60(x-2)
30x = 60x - 60*2
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30x = 60*2
x = 4 hrs (time for faster to catch up to slower)
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Cheers,
Stan H.
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