SOLUTION: A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite direction in 6 seconds. The speed of the train in km/h is how much?

Question 511706: A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite direction in 6 seconds. The speed of the train in km/h is how much?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A 150 metres long train crosses a man walking at the speed of 6km/h in the opposite direction in 6 seconds. The speed of the train in km/h is how much?
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Let "r" be the speed of the train.
rate = distance/time
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train rate (r km/hr)= r(km/hr)(1000 m/km)(hr/3600sec) = (r/3.6)(m/sec)
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man rate: 6(km/hr) = 6(1000/3600) = 6/3.6 = (1/0.6)(m/sec)
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Train distance in 6 sec = time*rate = 6(r/3.6) = r/0.6 meters
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Man distance in 6 sec = time*rate = 6(1/0.6) = 1/0.1 = 10 meters
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Equation:
train distance - man distance = 150 meters
(r/0.6) - 10 = 150
(r/0.6) = 140
r = 84 meters/sec
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Cheers,
Stan H.
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