You can
put this solution on YOUR website!I think your mistake is not putting parentheses around the time (t-1).
As you said,
let s = speed of the local
2s = speed of the express
t= time of the local
t-1 = time of the express
Distances are equal at 50 miles, so (rate times time) = (rate times time)
s*(t) = 2s *(t-1)
Since s the speed of the train does not equal zero, you can divide both sides by s:
t= 2(t-1)
t=2t -2
-t = -2
t=2 hours for the local
t-1 = 1 hour for the express
After you do that, then remember that D=RT, so
Rate for the local =
=25 mph
Rate for the express =
= 50 mph.
R^2 at SCC
