You can
put this solution on YOUR website!Of course the basic formula for this is D= RT.
Let t= time (in hours) required to arrive ON TIME
Change 1 minute early or late to

hour early or late.

= time required to arrive a minute late at 40 mph.

= time required to arrive a minute early at 45 mph.
Distance is the same either way he arrives, so RT = RT
Use distributive property to remove the parentheses:
Subtract 40t from each side:
Add

to each side:
Divide both sides by 5:

hours. (This means 17 minutes to arrive ON TIME!)
Distance = Rate * Time
(At 40)

= 12 miles, arriving 1 minute late.
(At 45)

= 12 miles, arriving 1 minute early.
Calculating distance both ways is a check!!
R^2 at SCC