SOLUTION: John drove his car into the shop to fix the oil leak in his engine. Once finished, his car was faster. He drove home in only 25 minutes when it took him 40 minutes to get there. If

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Question 503002: John drove his car into the shop to fix the oil leak in his engine. Once finished, his car was faster. He drove home in only 25 minutes when it took him 40 minutes to get there. If he was traveling an average of 32 miles per hour going there, how fast did he drive home?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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John drove his car into the shop to fix the oil leak in his engine.
Once finished, his car was faster. He drove home in only 25 minutes when it took him 40 minutes to get there.
If he was traveling an average of 32 miles per hour going there, how fast did he drive home?
:
Change minutes to hours
25%2F60 = 5%2F12 hrs
40%2F60 = 8%2F12 hrs
:
Let s = his speed going home
:
The distance there and back are equal, write a dist equation; Dist = time * speed
:
5%2F12s = 8%2F12(32)
mult both side by 12
5s = 8(32)
5s = 256
s = 256%2F5
s = 51.2 mph return speed
:
:
Confirm this by finding the distances, they should be equal
5%2F12*51.2 = 21.33 mi
8%2F12*32 = 21.33 mi