SOLUTION: can someone please help me?
A porsche and VW bug that were 450 miles apart traveled toward eachother. They met after 5 hours. If one car traveled twice as fast as the other, wha
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Question 500880: can someone please help me?
A porsche and VW bug that were 450 miles apart traveled toward eachother. They met after 5 hours. If one car traveled twice as fast as the other, what were their speed?
Answer by geetha_rama(94) (Show Source): You can put this solution on YOUR website!
Let x be the location of Porshe car and y be the lcoation of VW
distance between x and y = 450 miles
speed of porshe = a
speed of VW = b
b = 2a -> equation 1(speed of 1 car is twice the other)
After 5 hours, the cars meet.
i.e., both the cars together would have covered the 450 miles in between them
distance = spped * time
and hence 5a + 5b = 450
dividing by 5,
=> a+b = 90
3a = 90 (from equation 1)
a = 30
b = 2a = 60
Hence the speed of the cars are 30 miles/hour and 60 miles/hour
Check: 5a + 5b = 450 => 5*30 + 5* 60 = 150 + 300 = 450
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