SOLUTION: The problem is: Michael drove to a friend's house at a rate of 40mi/h. He returned by the same route at a rate of 45mi/h. the driving time for the round trip was 4 h. What was the

Question 50067: The problem is: Michael drove to a friend's house at a rate of 40mi/h. He returned by the same route at a rate of 45mi/h. the driving time for the round trip was 4 h. What was the distance Michael traveled?
I know the answer is about 170 miles because (45+40)/2 is 42.5 times 4 is 170. But how do you set up an algebraic equation to solve?
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
Let x be the distance
because time = distance/speed
45*40=1800

40x+45x=7200
85x=7200
x=84.7
the answer is not 170
Paul.
RELATED QUESTIONS
michael drove to a friends house at a rate of 40mi/h. he returned by the same route at a... (answered by stanbon)

Michael drove to a friend's house at a rate of 40 mi/h. He returned by the same route at... (answered by Alan3354)

Michael drove to a friend's house at a rate of 40 mph. He returned by the same route at a (answered by Alan3354)

Michael drove to a friend's house at a rate of 40mph. He returned by the same route at a... (answered by checkley77,richwmiller)

Micheal drove to a friends house at a rate of 40 mi/h. He returned by the same route at... (answered by Alan3354)

Michael drove to a friend`s house a rate of 40 mph. he came back by the same route, but... (answered by checkley77)

michaek drove to a friends house at a rate of 40 mph. he returned the same route at a... (answered by ankor@dixie-net.com)

30) Two planes left an airport at noon. One flew east at a certain speed and the other... (answered by stanbon)

Michael drove to a friends house at a rate of 40 mph. He returned by the same route at a... (answered by ramkikk66,josmiceli)