SOLUTION: boat A left a port at 7:00a.m.traveling at 30 miles per hour at 9:00a.m. boat B left the same port traveling at 40mph what time did boat B overtake boat A?

Question 499860: boat A left a port at 7:00a.m.traveling at 30 miles per hour at 9:00a.m. boat B left the same port traveling at 40mph what time did boat B overtake boat A?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
d = rt is the basic distance equation.
.
Boat A travels distance 'd' in time 't' at 30 mph.
Boat B travels distance 'd' in time 't-2' at 40 mph.
.
30t = 40 (t-2)
30t = 40t - 80
-10t = -80
t = 8
t-2 = 6
.
Boat A travels for 8 hrs at 30 mph for a distance of 240 miles.
Boat B travels for 6 hrs at 40 mph for a distance of 240 miles.
.
Since the two boats have traveled the same distance, then Boat B has caught up with Boat A.
.
Re-read the question to make sure you answer it.
.
What time did Boat B overtake Boat A?
9 a.m. + 6 hrs = 3 p.m.
.
Done.
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