SOLUTION: a jar of dimes and quarters contains $15.25. there are 103 coins in all. how many of each are there?
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Question 4978: a jar of dimes and quarters contains $15.25. there are 103 coins in all. how many of each are there?
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = number of quarters. The rest of the 103 coins are dimes, so
103 - x = number of dimes.
In order to work the whole problem in cents, change the $15.25 to cents: 1525 cents.
Value of quarters + value of dimes = Total value of coins
25(x) + 10(103 - x) = 1525
25x + 1030 - 10x = 1525
15x + 1030 = 1525
15x + 1030 - 1030 = 1525 - 1030
15x = 495
Quarters
Number of dimes
= 103 - x
= 103 - 33
= 70 Dimes
Check: Total value = $15.25
Quarters .25(33) = $8.25
Dimes .10(70) = 7.00
Total = $15.25
R^2 at SCC
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