SOLUTION: Two cyclists, 128 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of
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Question 491125: Two cyclists, 128 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
4(n+3n)=128
16n=128
n=8
3n=24
The faster cyclist is going 24 mi/h..
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