SOLUTION: 2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs
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Question 488890: 2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2 children are balanced on a seesaw. One of them weighing 40 lbs is 6 feet from the fulcrum. How far from the fulcrum on the other side must the other child sit if he weighs 60 lbs?
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Equation:
40*6 = 60x
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x = (40*6)/60
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x = 40/10
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x = 4 ft.
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Cheers,
Stan H.
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