You can
put this solution on YOUR website!A ---- North ---- 5 km/h
B----- east ------16km/h (After 1 hour)
let the time be t
A distance 5t+5
B distance 16 t
(5t+5)^2+(16t)^2=52^2 ( I have used x in place of t)
25t^2+50t+25+256t^2=52^2
281t^2+50t-2679 =0
Find the roots of the equation by quadratic formula
a= 281 b= 50 c= -2679
b^2-4ac= 2500 - 3011196
b^2-4ac= 3013696

= 1736
x1=( -50 + 1736 )/ 562
x1= 3 3
x2=( -50 -1736 ) / 562
x2= -3.18 -3 1/6
Ignore negative value
x = 3 hours
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