SOLUTION: a man drives regularly from his office to his home when he drives 36 kph he arrives home 3 minutes late than usual. When he drives 45 kph he arrives 3 minutes earlier than usual. F

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Question 485368: a man drives regularly from his office to his home when he drives 36 kph he arrives home 3 minutes late than usual. When he drives 45 kph he arrives 3 minutes earlier than usual. Find his usual and the distance from his office to his home?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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a man drives regularly from his office to his home when he drives 36 kph he arrives home 3 minutes late than usual.
When he drives 45 kph he arrives 3 minutes earlier than usual.
Find his usual driving time, and the distance from his office to his home?
:
Let t = his usual driving time
:
Change 3 min to hrs. 3%2F60 = .05 hrs
:
Write a dist equation, Dist = speed * time
:
45(t-.05) = 36(t+.05)
45t - 2.25 = 36t + 1.8
45t - 36t = 1.8 + 2.25
9t = 4.05
t = 4.05%2F9
t = .45 hrs which is; .45(60) = 27 minutes, his normal driving time
;
Find the distance when he is 3 min early (24 min)
45*24%2F60 = 18 km
:
Check the distance when he is 3 min late (30 min)
36*30%2F60 = 18 km
:
Summarize, 27 min normal drive time, 18 km is the distance