SOLUTION: An athlete decides to run the same distance in 1/4th less time that she usually took. By how
much percent will she have to increase her average speed?
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Question 480071: An athlete decides to run the same distance in 1/4th less time that she usually took. By how
much percent will she have to increase her average speed?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
d = r1*t
For 3/4 the time:
d = r2*(3t/4)
r1*t = r2*3t/4
r1 = r2*3/4
r2 = 4*r1/3
4/3 as fast, a 33 1/3% increase
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