# SOLUTION: Ok here is the problem. An airplane flying at a rate of 500 miles per hour leaves Los Angeles.One-half hour later,a second airplane leaves Los Angeles in the same direction flying

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 Question 477121: Ok here is the problem. An airplane flying at a rate of 500 miles per hour leaves Los Angeles.One-half hour later,a second airplane leaves Los Angeles in the same direction flying at a rate of 600 miles per hour.How long will it take the second airplane to overtake the first?Answer by ankor@dixie-net.com(15645)   (Show Source): You can put this solution on YOUR website!An airplane flying at a rate of 500 miles per hour leaves Los Angeles. One-half hour later,a second airplane leaves Los Angeles in the same direction flying at a rate of 600 miles per hour. How long will it take the second airplane to overtake the first? : Let t = the travel time of the 2nd airplane (faster) then (t+.5) = the travel time of the 1st airplane : When the 2nd plane catches up with the 1st they will have traveled the same distance. Write dist equation: dist = speed * time : Fast plane dist = slower plane dist 600t = 500(t+.5) 600t = 500t + 250 600t - 500t = 250 100t = 250 t = t = 2.5 hrs for the faster plane to catch the slower : : Confirm this by finding the dist each traveled, they should be equal 600*2.5 = 1500 mi 500(2.5+.5) = 1500 mi