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An airplane flying at a rate of 500 miles per hour leaves Los Angeles.
One-half hour later,a second airplane leaves Los Angeles in the same direction flying at a rate of 600 miles per hour.
How long will it take the second airplane to overtake the first?
Let t = the travel time of the 2nd airplane (faster)
(t+.5) = the travel time of the 1st airplane
When the 2nd plane catches up with the 1st they will have traveled the same distance.
Write dist equation: dist = speed * time
Fast plane dist = slower plane dist
600t = 500(t+.5)
600t = 500t + 250
600t - 500t = 250
100t = 250
t = 2.5 hrs for the faster plane to catch the slower
Confirm this by finding the dist each traveled, they should be equal
600*2.5 = 1500 mi
500(2.5+.5) = 1500 mi