SOLUTION: A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate o

Question 47677This question is from textbook Introductory Algebra
: A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car. This question is from textbook Introductory Algebra

Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
RT=R/2(T+5) OR RT=(RT+5R)/2 OR 2RT=RT+5R DIVIDING ALL TERMS BY R WE GET
2T=T+5 OR T=5 & RT=300 OR R*5=300 OR R=300/5 OR R=60 MPH FOR THE CAR
300/60=5 HOURS 300/30=10 HOURS THUS 10-5=5 HOURS DIFFERENCE.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car.
Bus DATA:
distance=300 mi; rate = x mi/hr; time=d/r = (300/x) hr.
Car DATA:
distance=300 mi; rate = rate = 2x mi/hr ; time = d/r = 300(2x) hr.
EQUATIOn:
car time = bus time - 5 hr.
300/2x = 300/x - 5
Divide thru by 300 to get:
1/2x = 1/x - 1/60
Multiply thru by 2x to get:
1 = 2 - x/30
-1=-x/30
x=30
2x=60 mph (The rate of the car)
Cheers,
Stan H.
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