SOLUTION: two cars start at the same point going opposite derections one travels 6mph faster than the other. in 4 houts they are 184 mile apart how fast were each going

Question 465008: two cars start at the same point going opposite derections one travels 6mph faster than the other. in 4 houts they are 184 mile apart how fast were each going

Found 2 solutions by jorel1380, nerdybill:
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
4(p+p+6)=184
8p+48=184
8p=136
p=17
p+6=23
The first car was going 17 mph, the second car went 23 mph..
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
two cars start at the same point going opposite derections one travels 6mph faster than the other. in 4 houts they are 184 mile apart how fast were each going
.
Let x = speed of slower car
then
x+6 = speed of faster car
.
4x + 4(x+6) = 186
dividing both sides by 4:
x + x+6 = 46.5
2x+6 = 46.5
2x = 40.5
x = 20.25 mph (slower car)
.
faster car:
x+6 = 20.25+6 = 26.25 mph
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