SOLUTION: A block is placed on an inclined plane. The acceleration of gravity is 9.8 m/s^2. A 26 N force is required to push the block up the incline with constant velocity. What is the heig

Question 460734: A block is placed on an inclined plane. The acceleration of gravity is 9.8 m/s^2. A 26 N force is required to push the block up the incline with constant velocity. What is the height of the block? Answer in units of N.
Mu=0.19
Angle= 21 degrees
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
I presume you mean "weight" instead of "height" because I don't think it's possible to find the height. Also, the weight, not the height, has units N.

Assuming

is the coefficient of kinetic friction, we can find the force of friction:

(F_n is the normal force).

However, we know that the frictional force must be 26 newtons; this is because "constant velocity" implies zero net force, so a 26 N pushing force must be counteracted by a 26 N frictional force. Also, if we were to label the components of the normal force, we will see that the normal force is equal to the weight times the cosine of the angle of the ramp. Hence,

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