SOLUTION: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=-16t^2+vt+s, wher

Question 458532: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=-16t^2+vt+s, where h is in feet. If the object is propelled from a height of 8 feet with an initial velocity of 64 feet per second, its height h is given by the equation h=-16t^2+64t+8.
After how many seconds is the height 68 feet?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..
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