# SOLUTION: I need to create a word problem and I am having a hard time setting up the problem once I create it. This is the word problem I have created. I took my son Go-Kart racing. One l

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 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Travel Word Problems Question 458514: I need to create a word problem and I am having a hard time setting up the problem once I create it. This is the word problem I have created. I took my son Go-Kart racing. One lap around the track is 804m. The worker releases my son on the track first and then releases me on the track 5 seconds later. My sons Go-Kart travels 6 mph and my Go-Kart travels 7mph. How long would it take me to pass my son on the track? I am thinking this is how I would set this up. x = my Go-Kart y = my sons Go-Kart t = the time it would take me to pass my son on the track Actually, I am pretty much lost and not even sure if I have an accurate word problem or I need to tweek the word problem in order to get an answer.Answer by josmiceli(9671)   (Show Source): You can put this solution on YOUR website!Is the 804 meters or miles? I assume it's miles. If not, just do a conversion. The key is: how much of a head start does your son have? sec = hrs In 5 seconds at 6 mi/hr, he goes mi mi head start Now you start a stopwatch when you are released. Your equation is: (1) (t is in hours) Your Son's equation is: (2) ( you both will have the same t now) and (3) You have 3 equations and 3 unknowns, so it's solvable Substitute (1) and (2) in (3) (3) (3) hrs Now convert to seconds: hrs x sec/hr = sec It will take you 30 sec to pass your son ------------------------------ You will have gone mi That is ft