# SOLUTION: Roger can run one mile in 16 minutes. Jeff can run one mile in 14 minutes. If Jeff gives Roger a 1 minute head start, how long will it take before Jeff catches up to roger? How far

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 Question 455673: Roger can run one mile in 16 minutes. Jeff can run one mile in 14 minutes. If Jeff gives Roger a 1 minute head start, how long will it take before Jeff catches up to roger? How far will each have run?Answer by stanbon(57369)   (Show Source): You can put this solution on YOUR website!Roger can run one mile in 16 minutes. Jeff can run one mile in 14 minutes. If Jeff gives Roger a 1 minute head start, how long will it take before Jeff catches up to roger? How far will each have run? -------------- Roger DATA: rate = 1/16 mile/minute ; time = x minutes distance = rt = x/16 miles ------ Jeff DATA: rate = 1/14 mile/minute ; time = x-1 minutes ; distance = rt = (x-1)/14 miles ============================================= Equation: distance = distance x/16 = (x-1)/14 14x = 16x-16 2x = 16 x = 8 minutes (Roger time) Roger will run rt = (1/16)8 = 1/2 mile x-1 = 7 minutes (Jeff time) Jeff will run rt = (1/14)7 = 1/2 mile ================================ Cheers, Stan H. ==============