SOLUTION: I am having trouble grasping the setup of a distance word problem. Here's an example. She travels to work at 39 mph. Her return trip home she traveled 29 mph and it took 1/2 hour l

Question 455119: I am having trouble grasping the setup of a distance word problem. Here's an example. She travels to work at 39 mph. Her return trip home she traveled 29 mph and it took 1/2 hour longer. What is the distance to work.
If someone could show me the example of how to set it up I think I can pick it up from there.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
She travels to work at 39 mph.
Her return trip home she traveled 29 mph and it took 1/2 hour longer.
What is the distance to work.
:
Let d = the distance to work
:
Write a time equation: time = dist/speed
:
29 mph time - 39 mph time = .5 hrs
- = .5
:
Multiply it by (29*39) to clear the denominators, results
39d - 29d = .5(29*39)
10d = 565.5
d =
d = 56.55 mi to work
:
:
See if this works out
- =
1.95 - 1.45 = .5; confirms our solution
:
:
Did this make sense to you?
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