SOLUTION: Flight 725 left New York at 10:28 a.m. flying north. Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred twenty kph less than three times the speed of f

Question 454654: Flight 725 left New York at 10:28 a.m. flying north. Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred twenty kph less than three times the speed of flight 725. At 1:06 p.m. they are 1,030 kilometers apart. From the information given in question 14, what is the average rate of speed for Flight 725?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Flight 725 left New York at 10:28 a.m. flying north.
Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred
twenty kph less than three times the speed of flight 725.
At 1:06 p.m. they are 1,030 kilometers apart.
What is the average rate of speed for Flight 725?
:
Let s = speed of flt 725
then it says:
"Flt 245 at one hundred twenty kph less than three times the speed of flight 725."
therefore:
(3s-120) = speed of flt 245
:
Find the flying time of each aircraft change 1:06 to 13:06
Flt 725: 13:06 to 10:28: 12:66 - 10:28 = 2 hr 38 min or = 79/30 hrs
Flt 245: 13:06 to 11:18: 12:66 - 11:18 = 48 min or hrs
:
Write a distance equation: dist = speed * time
:
Flt 725 dist + Flt 245 dist = 1030 km
s + (3s-120) = 1030
Multiply by 30, results:
79s + 6*4(3s-120) = 30(1030)
79s + 24(3s-120) = 30900
79s + 72s - 2880 = 30900
151s = 30900 + 2880
151s = 33780
s =
s = 223.7 km/hr is flt 725

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