SOLUTION: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of
Algebra.Com
Question 453354: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of 10km/h. how long does the submarine need to travel before the ships are 150km apart?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
3x10 kph+20x=150
20x=120
x=6
It will be 6 hours before the two craft are 150 km apart..
RELATED QUESTIONS
A submarine left the Azores and traveled
west. Three hours later an aircraft carrier... (answered by ankor@dixie-net.com)
an aircraft carrier left port 31 and traveled west at an avarage speed of 14 mph.some... (answered by ankor@dixie-net.com)
An aircraft carrier left Diego Garcia and traveled toward St. Vincent at an average speed (answered by mananth)
An aircraft carrier left the Pier 53 and traveled north. An container ship left 1 hour... (answered by ankor@dixie-net.com)
A cruise ship left Port 37 and traveled south. A submarine left nine hours later... (answered by josmiceli)
A container ship left the Azores and traveled west . Six hours later an aircraft carrier... (answered by greenestamps,josgarithmetic)
A submarine left Hawaii travelling west four hours before an aircraft carrier. The... (answered by ikleyn)
A container ship left thr Dania Pier and traveled north. An aircraft carrier left four... (answered by stanbon,solver91311)
A container ship left the Danie Pier and traveled north. An aircraft carrier left four... (answered by mananth)