SOLUTION: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second. If v=19 feet per

Question 452048: When a ball is thrown, its height in feet h after t seconds is given by the equation
h=vt-16t^2
where v is the initial upwards velocity in feet per second. If v=19 feet per second, find all values of t for which h=5 feet. Do not round any intermediate steps. Round your answer to 2 decimal places.
t= ? seconds
Could there be more than one answer? If so, what are all answers?
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
When a ball is thrown, its height in feet h after t seconds is given by the equation
h=vt-16t^2 -> -16t^2 + vt - h = 0
Given: v=19 fps
Find all values of t for which h=5 ft.
We need to solve the quadratic equation for t:
-16t^2 + 19t - 5 = 0
t = (-19 +- sqrt(19^2 -4(16)(5)))/-32
This gives t = 0.39, 0.79
So the two times are t = 0.39 s and 0.79 s.
The graph of the ball's trajectory is below:

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