Hi,

h(t)=60t-16t^2 |What is the maximum height that the ball will reach?

Using the vertex form of a parabola,  where(h,k) is the vertex

h(t)= -16t^2 + 60t   |completing the Square

h(t)= -16[(t-15/8)^2 - 225/64]

h(t)= -16(t-15/8)^2 + 225/4    |parabola opening downward: V(1.875,56.25)

maximum height that the ball will reach is 225/4 = 56.25 ft 

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