SOLUTION: On monday roger drove to work in 16 minutes. Tuesday he averaged 11mph more and it took him 4 minutes less. How far does he travel to work? how would you set this problem up? an

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Question 449358: On monday roger drove to work in 16 minutes. Tuesday he averaged 11mph more and it took him 4 minutes less. How far does he travel to work?
how would you set this problem up? and solve? Thanks!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
On monday roger drove to work in 16 minutes.
Tuesday he averaged 11mph more and it took him 4 minutes less.
How far does he travel to work?
how would you set this problem up?
:
Let s = his speed on Monday
then
(s+11) = his speed on Tuesday and it takes him 16-4 = 12 min
:
Times have to be in hrs
:
Write a distance equation, dist = speed * time
:
Mon dist = Tues dist
s * 16%2F60 = (s+11) * 12%2F60
multiply both sides by 60
16s = 12(s+11)
16s = 12s + 132
16s - 12s = 132
4s = 132
s = 132%2F4
s = 33 mph on monday
then
33 + 11 = 44 mph on Tues
:
Find the dist
33 * 16%2F60 = 8.8 miles
:
Check it on Tuesday, should be the same
44 * 12%2F60 = 8.8 mi