SOLUTION: a backpacker hiking into a wilderness area walked 9 mi at a constant rate and then reduced this rate by 1 mph. another 4 mi was hiked at the reduced rate. the time required to hike
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Question 447459: a backpacker hiking into a wilderness area walked 9 mi at a constant rate and then reduced this rate by 1 mph. another 4 mi was hiked at the reduced rate. the time required to hike the 4 mi was 1 h less than the time required to walk the 9 mi. find the rate at which the hiker walked the first 9 mi.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
9/x=4/(x-1)+1
9(x-1)=4x+(x)(x-1)
9x-9=4x+x2-x
0=x2-6x+9
(x-3)2=0
x=3
The hiker walked the first 9 miles at 3 mph..
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