SOLUTION: A person jogs 3.5 miles and walks and additional 4 miles. He jogs 4.5 mph faster than he walks. The total exercise time is 6 hrs. Find the speeds.

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Question 434776: A person jogs 3.5 miles and walks and additional 4 miles. He jogs 4.5 mph faster than he walks. The total exercise time is 6 hrs. Find the speeds.
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
Let x be the person's walking speed.
------------------------------
4/x+3.5/(x+4.5)=6
Multiply each side by (x)(x+4.5)
4(x+4.5)+3.5(x)=6(x2+4.5x)
4x+18+3.5x=6x2+27x
8x+36+7x=12x2+54x
0=12x2+39x-36
0=(4x-3)(3x+12)
x=3/4,-4
His walking speed is .75 mph, jogging is 5.25
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3249 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.75, -4. Here's your graph:

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