SOLUTION: A baseball diamond is actually a square,90 feet on a side. what is the distance from home plate to 2nd base(which is the diagonal of the square)? round to the nearest foot

Question 430294: A baseball diamond is actually a square,90 feet on a side. what is the distance from home plate to 2nd base(which is the diagonal of the square)? round to the nearest foot
Found 2 solutions by algebrahouse.com, Alan3354:
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"A baseball diamond is actually a square,90 feet on a side. what is the distance from home plate to 2nd base(which is the diagonal of the square)? round to the nearest foot"

A right triangle is formed, with the distance from home to 2nd being the hypotenuse.
From home to 1st and 1st to second are the legs.

a^2 + b^2 = c^2 {the pythagorean theorem}
90^2 + 90^2 = c^2 {substituted into the pythagorean theorem}
8100 + 8100 = c^2 {squared the 90's}
16,200 = c^2 {combined like terms}
c = 127 {took square root of both sides and rounded to nearest foot}
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
90*sqrt(2)
= 127 feet
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