SOLUTION: swimming with the current for 36 minutes, i traveled 1.5 miles. Swimming back to where i started against the current it took 1 hour. what is the rate at which i swam in still water
Algebra.Com
Question 427802: swimming with the current for 36 minutes, i traveled 1.5 miles. Swimming back to where i started against the current it took 1 hour. what is the rate at which i swam in still water? What is the rate of the current?
----- i cannot figure out how to start this problem.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
swimming with the current for 36 minutes, i traveled 1.5 miles.
Swimming back to where i started against the current it took 1 hour.
what is the rate at which i swam in still water?
What is the rate of the current?
:
Let s = swim speed in still water
Let c = rate of the current
:
Change 36 min to .6 hrs
:
Write two distance equation, one for each way, Dist = speed * time
.6s + .6c = 1.5
and
1s - 1c = 1.5
s = (c + 1.5)
:
replace s with (c+1.5) in the 1st equation
.6(c + 1.5) + .6c = 1.5
.6c + .9 + .6c = 1.5
1.2c = 1.5 - .9
1.2c = .6
c =
c = .5 mph is the current
:
Find s using the 2nd equation
s - .5 = 1.5
s = 1.5 + .5
s = 2 mph is the swimming speed
:
:
Check solutions in the 1st equation
.6(2) + .6(.5) = 1.5
1.2 + .3 = 1.5
RELATED QUESTIONS
I need help setting up this Linear Equation: While on vacation, Kevin went for a swim... (answered by dfrazzetto,mananth)
What could be the system of linear equations for this problem if i want to use... (answered by ankor@dixie-net.com)
Here is another one I would need help with:
Kevin was swimming agains the current, it... (answered by josmiceli)
Brian decides to start training for swimming in a river. The current in the river is... (answered by jim_thompson5910)
word problem: Malik canoed against the current for 2 hours and then with the current for (answered by lynnlo)
It takes James and Bret 15 minutes to travel 5 miles upstream against the current. The... (answered by stanbon)
Okay, I have another one using distance = rate times time but it has a twist. I am... (answered by Fombitz)
I am hoping you could help me with a problem I have with solving application problems... (answered by vleith)
Steve’s canoe goes 14km/hr in still water. He paddled for 2 hours with the current to... (answered by josmiceli)