# SOLUTION: A train left Town A at 8:50 a.m., it passed Town B at 9:30 a.m. and arrived at Town C at 10:30 a.m. The distance between Town A and Town B is 100 km. Between Town B and Town C, th

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: A train left Town A at 8:50 a.m., it passed Town B at 9:30 a.m. and arrived at Town C at 10:30 a.m. The distance between Town A and Town B is 100 km. Between Town B and Town C, th      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Question 425907: A train left Town A at 8:50 a.m., it passed Town B at 9:30 a.m. and arrived at Town C at 10:30 a.m. The distance between Town A and Town B is 100 km. Between Town B and Town C, the train travelled at 110 km/h. What was the average speed of the train for the whole journey? Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!A to B is 100 km B to c speed 110 km/h traveled for 1 hour so distance = 110 km. Total distance = 210 km Total time = 10:30 - 8:50 = 1 h 40 minutes = 1 2/3 hours===> 5/3 hours Rate = distance / time Rate = 210/(5/3) Rate = 210*3/5 Rate = 42*3 Rate = 126 km/h ====> average speed of the journey