SOLUTION: Lucas ran away from home at 7:15 p.m. running at a rate of 5 kph. His father set out after him 15/2 hours later. At what time did the father overtake the son if he was able to purs

Question 422314: Lucas ran away from home at 7:15 p.m. running at a rate of 5 kph. His father set out after him 15/2 hours later. At what time did the father overtake the son if he was able to pursue at the rate of 8 kph?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Lucas speed 5 kph
father's rate 8 kph

Difference in time= 7.5 hours (15/2) hours
Lucas will have covered 37.5 km father starts

catch up distance=37.5 km
catch up speed = 8-5 kph
catch up speed = 3 kph

Catchup time = catchup distance/catch up speed
catch up time=37.5/3
catch up time= 12.5 hours

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