SOLUTION: A man walks for 2 hours - on the way there he walks straight at 4/km per hour and uphill to the point at 3/km per hour. On the way back he walks downhill at 6/km per hour and strai
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Question 421877: A man walks for 2 hours - on the way there he walks straight at 4/km per hour and uphill to the point at 3/km per hour. On the way back he walks downhill at 6/km per hour and straight at 4/km per hour. How many kilometers has he travelled in total after 2 hours?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A man walks for 2 hours - on the way there he walks straight at 4/km per hour
and uphill to the point at 3/km per hour.
On the way back he walks downhill at 6/km per hour and straight at 4/km per hour.
How many kilometers has he traveled in total after 2 hours?
:
Let f = dist of level ground
Let h = dist of the hill
:
Write a time equation: Time = dist/speed
:
lev time + uphill time + downhill time + lev time = 2 hrs
+ + + = 2
combine like terms, use common denominator for the hill times
+ + = 2
+ = 2
;
Multiply by 12, results
3(2f) + 2(3h) = 12(2)
6f + 6h = 24
:
Simplify, divide by 6
f + h = 4 km is one way distance
therefore
total dist in 2 hrs = 8 km
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