SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 60 miles per hour and train B is traveling at 80 miles per hour. Train A passes a st

Question 417941: Trains A and B are traveling in the same direction on parallel tracks. Train A
is traveling 60 miles per hour and train B is traveling at 80 miles per hour.
Train A passes a station at 6:10 P.M.. If train B passes the same station at
6:22 P.M., at what time will train B catch up to train A?

Found 2 solutions by lwsshak3, mananth:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks. Train A
is traveling 60 miles per hour and train B is traveling at 80 miles per hour.
Train A passes a station at 6:10 P.M.. If train B passes the same station at
6:22 P.M., at what time will train B catch up to train A?
..
let x=time(hours)train B catches up with train A after passing the station.
x+12/60=(x+1/5)hours train A would have traveled when train B catches up to train A.
Distance=speed*travel time.
Both trains covered the same distance.
80x=60(x+1/5)
80x=60x+12
20x=12
x=12/20=3/5 hour or 36 minutes
ans:
Train B will catch up to train A at 6:58 PM

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Train A speed 60mph
Train B speed 80mph

Train A passes station at 06:10
Train B passes station at 06:22

Difference in time=00:12 12minutes
Train A will have covered 12miles before Train B starts

catch up distance=12 miles
catch up speed =80-60 mph
catch up speed =20mph

Catchup time = catchup distance/catch up speed
catch up time= 12/20
catch up time= 0.6 hours
catch up time= 36 minutes
Add this to 6.22 = 6.58 pm
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