SOLUTION: Sam leaves on a long trip driving at a steady rate of 45mph. Allen leaves from the same location traveling the same distance 2 hours later. He drives at a steady rate of 55mph.

Question 415742: Sam leaves on a long trip driving at a steady rate of 45mph. Allen leaves from the same location traveling the same distance 2 hours later. He drives at a steady rate of 55mph. How long after Allen leaves home will he catch up to Sam?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

Let x and ( x-2hr) represent the times that Sam and Allen traveled respectively

 Question states***  D = r*t  (distances being the same for both

 45mph*x = 55mph(x-2)

Solving for x

    110 = 10x

     11hr = x, time Sam traveled.  Allen traveled 9 hrs.



CHECKING our Answer***

45mph*11hr = 55mph*9hr = 495mi 

RELATED QUESTIONS

Shelia leaves on a long trip driving at a steady rate of 30mph. Her sister Allison leaves  (answered by ankor@dixie-net.com)
Shelia leaves on a long trip driving at a steady rate of 40 miles per hour.  Her sister... (answered by fractalier)
candice leaves on a trip driving at a steady rate of 35 miles per hour. Her sister liz... (answered by josgarithmetic)
Sheila leaves on a long trip driving at a steady rate of 30 miles per hour. Her sister... (answered by nayha)
I am not shore how do do this please help.
Girl A leaves on a long trip driving at a... (answered by Alan3354)
Shelia leaves on a long trip traveling 30mph.  Allison leaves the same location traveling  (answered by doctor_who)
Sheila leaves on a long trip driving at a steady rate of 25 miles per hour. Her sister... (answered by algebrahouse.com)
Candice Leaves on a road trip driving at 25 miles per hour . Four hours later , her... (answered by josmiceli)
Sara leaves at 7am at a rate of 45mph
Mark leaves at 7:30am at a rate of 55mph
They... (answered by ankor@dixie-net.com)