SOLUTION: Steve and Matt want to meet in Atlanta. Steve must travel 195 miles, while Matt must travel only 165 miles. If Steve's average speed is 10 miles per hour faster than Matt's and bot

Question 415657: Steve and Matt want to meet in Atlanta. Steve must travel 195 miles, while Matt must travel only 165 miles. If Steve's average speed is 10 miles per hour faster than Matt's and both require the same amount of time to get to Atlanta, at what average speed must each travel?
Found 2 solutions by dnanos, mananth:
Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
Matt's speed let x
Steve's speed x+10
Matt's time = 165/x
Steve's time= 195/(x+10)
Both require the same amount of time:
165/x=195/(x+10)
165(x+10)=195x
165x+1650=195x
165x-195x=-1650
-30x=-1650
3x=165
x=165/3
x=55
55mph for Matt
and
x+10=55+10
65mph for Steve.

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
matt speed= x
Steve speed= 10 mph faster

Matt distance 165
Steve distance 195
165/x=195/x+10
cross multiply
165(x+10 )=195x
165x+1650=195x
195x-165 x=1650
30x=1650
/30
x=55 mph matt speed

65 mph Steve speed

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