# SOLUTION: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the      Log On

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 Question 412273: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the rate of the wind? Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi Let x and y represent the speed of the jet and wind respectively Question states*** d = r*t 7x - 7y = 6440 3x + 3y = 3780 |multiplying thru with 7/3 to eliminate y 7x - 7y = 6440 7x + 7y = 8820 14x = 15260 x = 1090mph, speed of jet y = (7*1090 - 6440)/7 |substituting into 1st Eq y = 170 CHECKING our Answer*** 3*1090 + 3*170 = 3780 ```