SOLUTION: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 412273: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the rate of the wind?
Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x and y represent the speed of the jet and wind respectively

Question states*** d = r*t

 7x - 7y = 6440

 3x + 3y = 3780 |multiplying thru with 7/3 to eliminate y



 7x - 7y = 6440

 7x + 7y = 8820

    14x =  15260

      x = 1090mph, speed of jet

      y = (7*1090 - 6440)/7   |substituting into 1st Eq

      y = 170

CHECKING our Answer***

3*1090 + 3*170 = 3780